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Question Number 126538 by Ndala last updated on 21/Dec/20

$$ifa+b⩾c>0$$ $$Provethat\frac{a}{1+a}+\frac{b}{1+b}>\frac{c}{1+c}$$ $$.$$ $$\mathrm{I}\mathrm{need}\mathrm{your}\mathrm{help},\mathrm{please}!$$

Commented byMJS_new last updated on 21/Dec/20

$$a+b⩾c>0\mathrm{means}a\mathrm{xor}b\mathrm{could}\mathrm{be}<0\mathrm{i}.\mathrm{e}.$$ $$a=5,b=-3,c=1$$ $$\mathrm{or}a>0\wedge b>0?$$

Commented byNdala last updated on 21/Dec/20

$$a,b\in \mathrm{R}$$ $$\mathrm{Can}\mathrm{you}\mathrm{help}\mathrm{me}?$$

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