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Question Number 126567 by sdfg last updated on 21/Dec/20

Answered by physicstutes last updated on 22/Dec/20

$$\mathbf{A}=(k,k)\mathrm{and}\mathbf{B}=(-3,4)$$$$\mathbf{A}.\mathbf{B}=\mid \mathbf{A}\mid \mid \mathbf{B}\mid \cos \theta$$$$\Rightarrow -3k+4k=k$$$$\Rightarrow k=\sqrt{k^2+k^2}.\sqrt{{(-3)}^2+4^2}\cos \theta$$$$k=5\sqrt{2}k\cos \theta$$$$\mathrm{or}\cos \theta =\frac{1}{5\sqrt{2}}\Rightarrow \theta =360°n\pm 81.9°,n\in \mathbb{Z}$$

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