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Question Number 126657 by adeyemiprof40 last updated on 23/Dec/20

Answered by Olaf last updated on 23/Dec/20

a^4 +a^3 +a^2 +a+1 = 0 ⇔ ((a^5 −1)/(a−1)) = 0, a≠1 ⇔ a^5 = 1 a≠1 a = e^((2/5)ikπ) , k = 1, 2, 3, 4 a^(2.....000) +a^(20....010) +1 = 1+1+1 = 3

a4+a3+a2+a+1=0⇔a5−1a−1=0,a≠1⇔a5=1a≠1a=e25ikπ,k=1,2,3,4a2.....000+a20....010+1=1+1+1=3

Answered by AlagaIbile last updated on 23/Dec/20

a^5 = 1 Therefore the require answer is ⇒ 1 + 1 + 1 = 3

a5=1Thereforetherequireansweris⇒1+1+1=3

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