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Question Number 126704 by Dwaipayan Shikari last updated on 23/Dec/20

$$\frac{e^{\pi }-1}{e^{\pi }+1}=\frac{\pi }{2+\frac{{\pi }^2}{6+\frac{{\pi }^2}{10+\frac{{\pi }^2}{14+....}}}}$$

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