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Question Number 126773 by Ar Brandon last updated on 24/Dec/20

Answered by Dwaipayan Shikari last updated on 24/Dec/20

A^→ +B^→ +C^→ =0i^� +j^� +0k^�   5i^� −j^� +4k^� +C^→ =j^�   C^→ =−5i^� +2j^� −4k^�

$$\overset{\rightarrow} {{A}}+\overset{\rightarrow} {{B}}+\overset{\rightarrow} {{C}}=\mathrm{0}\hat {{i}}+\hat {{j}}+\mathrm{0}\hat {{k}} \\ $$$$\mathrm{5}\hat {{i}}−\hat {{j}}+\mathrm{4}\hat {{k}}+\overset{\rightarrow} {{C}}=\hat {{j}} \\ $$$$\overset{\rightarrow} {{C}}=−\mathrm{5}\hat {{i}}+\mathrm{2}\hat {{j}}−\mathrm{4}\hat {{k}} \\ $$$$ \\ $$

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