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Question Number 126803 by john_santu last updated on 24/Dec/20
B(73,23)=?B=bethafunction
Answered by Dwaipayan Shikari last updated on 24/Dec/20
B(73,23)=Γ(73)Γ(23)Γ(3)=Γ(13)Γ(23).43.132!=29.πsinπ3=4π93
Answered by liberty last updated on 24/Dec/20
B(73,23)=Γ(73).Γ(23)Γ(73+23)=Γ(73).Γ(23)Γ(3)[Γ(3)=(3−1)!=2][Γ(x+1)=xΓ(x)]⇔=43.13.Γ(13).Γ(23)2=29.Γ(13).Γ(23)[Γ(x).Γ(1−x)=πsin(πx);x∉Z]⇔=29.πsin(π3)=4π93=43π27
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