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Question Number 126989 by arash sharifi last updated on 25/Dec/20

$$\int e^{\sqrt{x}}dx$$

Answered by bramlexs22 last updated on 26/Dec/20

$$let\sqrt{x}=u\Rightarrow x=u^2$$$$dx=2udu$$$$I=\int 2u{e}^{u}du...\left(byparts\right)$$$$I=2{ue}^u-2e^u+c$$$$I=2\sqrt{x}{e}^{\sqrt{x}}-2e^{\sqrt{x}}+c$$

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