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Question Number 127018 by '-E/9 last updated on 26/Dec/20

Vf×2=Vi×2+2aΔd  0=16.5

$${Vf}×\mathrm{2}={Vi}×\mathrm{2}+\mathrm{2}{a}\Delta{d} \\ $$$$\mathrm{0}=\mathrm{16}.\mathrm{5} \\ $$

Answered by physicstutes last updated on 26/Dec/20

you should write it this way.    v_f ^2  = v_i ^2  + 2aΔd  but please don′t learn how to write your equations  in a forum where everyone will see it.

$$\mathrm{you}\:\mathrm{should}\:\mathrm{write}\:\mathrm{it}\:\mathrm{this}\:\mathrm{way}. \\ $$$$\:\:{v}_{{f}} ^{\mathrm{2}} \:=\:{v}_{{i}} ^{\mathrm{2}} \:+\:\mathrm{2}{a}\Delta{d} \\ $$$$\mathrm{but}\:\mathrm{please}\:\mathrm{don}'\mathrm{t}\:\mathrm{learn}\:\mathrm{how}\:\mathrm{to}\:\mathrm{write}\:\mathrm{your}\:\mathrm{equations} \\ $$$$\mathrm{in}\:\mathrm{a}\:\mathrm{forum}\:\mathrm{where}\:\mathrm{everyone}\:\mathrm{will}\:\mathrm{see}\:\mathrm{it}. \\ $$

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