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Question Number 12705 by @ANTARES_VY last updated on 29/Apr/17

this  y=sin(x/2)  find the  range  of  the  function.

thisy=sinx2findtherangeofthefunction.

Answered by Joel577 last updated on 29/Apr/17

Range  −1 ≤ y ≤ 1

Range1y1

Commented by @ANTARES_VY last updated on 29/Apr/17

how does  it  work?

howdoesitwork?

Commented by arnabpapu550@gmail.com last updated on 09/Jun/17

As range of sinθ , cosθ ∈[−1,+1]  ∴ sin(x/2)∈[−1,+1]

Asrangeofsinθ,cosθ[1,+1]sinx2[1,+1]

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