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Question Number 12713 by ashok kumar last updated on 29/Apr/17

$$\mathit{Q}.\mathit{\theta }={\tan }^{-1}4/3$$$$$$

Commented by prakash jain last updated on 01/May/17

$$\mathrm{agar}\mathrm{ye}\mathrm{textbook}\mathrm{ka}\mathrm{question}\mathrm{hai}$$$$\mathrm{to}\mathrm{trigonometric}\mathrm{tables}\mathrm{se}\mathrm{amswer}$$$$\mathrm{aa}\mathrm{sakta}\mathrm{hai}.$$

Answered by mrW1 last updated on 29/Apr/17

$${\tan }^{-1}\left(4/3\right)\approx 53.13°$$

Commented by mrW1 last updated on 29/Apr/17

$$I{don}^{\prime }tunderstandyou.$$

Commented by ashok kumar last updated on 29/Apr/17

$$howtoyou53.13°$$

Commented by mrW1 last updated on 29/Apr/17

$$Iusedacalculatorwithtrigonometric$$$$functions.$$$$$$$$\tan 45°=1$$$$\tan 60°=\sqrt{3}\approx 1.732$$$$since\tan \theta =\frac{4}{3}\approx 1.333$$$$\Rightarrow \theta mustbebetween45°and60°.$$

Commented by ashok kumar last updated on 29/Apr/17

$$keseayesirpleasebato$$

Commented by prakash jain last updated on 01/May/17

$$\mathrm{Ashok},\mathrm{trigonometric}\mathrm{tables}\mathrm{se}$$$$\mathrm{bhi}\mathrm{aa}\mathrm{sakta}.\mathrm{Kya}\mathrm{aapko}\mathrm{trigonometric}$$$$\mathrm{tables}\mathrm{padna}\mathrm{aata}\mathrm{hai}?$$

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