From 1 to 50 (1 and 50 includes) fev n for (((n^2 −1)!)/((n!)^n )) full number


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Question Number 127414 by MathSh last updated on 29/Dec/20

$F r o m 1 t o 50 (1 a n d 50 i n c l u d e s)$ $f e v n f o r \frac{(n^{2} - 1)!}{{(n!)}^{n}} f u l l n u m b e r$
Commented by talminator2856791 last updated on 29/Dec/20

$what is fev ?$
Commented by MathSh last updated on 29/Dec/20

$F r o m 1 t o 50 h o w m a n y n n u m b e r s$ $w h i c h i s \frac{(n^{2} - 1)}{{(n!)}^{n}} i s i n t e g e r . .$
Commented by talminator2856791 last updated on 29/Dec/20

$oooooohhhhhhh$
Commented by MathSh last updated on 29/Dec/20

$S o r r y s i r, s o l u t i o n p l e a s e . .$
	Answered by talminator2856791 last updated on 08/Sep/21

	$n^{2} - 1 = (n + 1) (n - 1)$ $\Rightarrow prime n + 1 dont satisfy conditions .$ $You can't use 'macro parameter character #' in math mode$ $50 - 15$ $= 35$
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