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Question Number 127519 by O Predador last updated on 30/Dec/20

Answered by mahdipoor last updated on 30/Dec/20

0.0833...=0.083^− =0.08+0.003^− = (8/(100))+(1/(300))=((25)/(300))=(1/(12))=((1×2)/(1×2×3×4))=((2!)/(4!))=(([log_2 (x^2 )−2]!)/([log_2 (x)+2]!)) ⇒x=4

0.0833...=0.083−=0.08+0.003−=8100+1300=25300=112=1×21×2×3×4=2!4!=[log2(x2)−2]![log2(x)+2]!⇒x=4

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