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Question Number 127525 by Mathgreat last updated on 30/Dec/20
Commented by Mathgreat last updated on 30/Dec/20
x1+x2+x3+...+xn=???
please
Answered by MJS_new last updated on 31/Dec/20
x7/3=xnn∈N(?)n=0⇒x7/3=1⇒x=1n⩾1(1)ifwestayinR⇒−x3=−x3⇒{n=2k;x=0∨x=1n=2k+1;x=−1∨x=0∨x=1(2)ifwe′reinC⇒−x3=abs(x)3eiarg(x)/3⇒x=0∨x=1
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