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Question Number 127566 by Ar Brandon last updated on 30/Dec/20
Answered by bramlexs22 last updated on 30/Dec/20
(a→+b→)×(a→−b→)=a→×a→−a→×b→+b→×a→−b→×b→[a→×a→=0;a→×b→=−b→×a→]=0+2(b→×a→)−0=2(b→×a→)
Commented by Ar Brandon last updated on 31/Dec/20
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