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Question Number 127605 by pticantor last updated on 31/Dec/20

$$findarg\left(z\right)$$$$where\mathit{z}=1+\mathit{c}\mathit{o}\mathit{s}\alpha +icos\beta$$

Answered by MJS_new last updated on 31/Dec/20

$$\arg (1+\cos \alpha +\mathrm{i}\cos \beta )=$$$$=\frac{\pi }{2}\mathrm{sign}\left(\cos \beta \right)-\arctan \frac{1+\cos \alpha }{\cos \beta }$$

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