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Question Number 127739 by Algoritm last updated on 01/Jan/21
Commented by Ndala last updated on 01/Jan/21
y,z∈N7z>0⇔2y−y6>0⇔0⩽y⩽1f(y)=2y−y6⇔⇒f(0)=f(1)=1⇒7z=1⇒z=0S={(1;0);(0;0)}
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