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Question Number 127859 by AgnibhoMukhopadhyay last updated on 02/Jan/21

Answered by liberty last updated on 03/Jan/21

$$\frac{3-5\mathrm{i}}{8+2\mathrm{i}}\times \frac{8-2\mathrm{i}}{8-2\mathrm{i}}=\frac{24-46\mathrm{i}-10}{64+4}=\frac{14-46\mathrm{i}}{68}$$$$=\frac{7}{34}-\frac{23\mathrm{i}}{34}$$

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