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Question Number 127912 by PRITHWISH SEN 2 last updated on 03/Jan/21

$$\mathrm{Dividing}\mathrm{by}\mathrm{the}\mathrm{factor}\mathrm{of}\mathrm{divisor}\mathrm{find}\mathrm{the}$$$$\mathrm{quotient}\mathrm{and}\mathrm{remainder}\mathrm{of}715\mathbf{÷}12$$

Answered by physicstutes last updated on 03/Jan/21

$$715=12\left(59\right)+7$$$$\mathrm{remainder}=7$$

Commented by PRITHWISH SEN 2 last updated on 03/Jan/21

$$\mathrm{thank}\mathrm{you}\mathrm{sir}.\mathrm{But}\mathrm{the}\mathrm{question}\mathrm{is}{}^{\prime }\mathbf{division}\mathbf{by}$$$$\mathbf{the}\mathbf{factor}\mathbf{of}\mathbf{the}{\mathbf{divisor}}^{\prime }\mathrm{not}\mathrm{divide}\mathrm{by}\mathrm{the}$$$$\mathrm{divisor}\mathrm{itself}.$$

Commented by mr W last updated on 03/Jan/21

$$andwhatismeantwiththat?$$

Commented by PRITHWISH SEN 2 last updated on 03/Jan/21

$$\mathrm{actually}\mathrm{I}\mathrm{am}\mathrm{also}\mathrm{confused}.\mathrm{This}\mathrm{is}\mathrm{what}\mathrm{I}\mathrm{found}$$$$\mathrm{on}\mathrm{a}5\mathrm{th}\mathrm{grade}\mathrm{maths}\mathrm{book}.$$

Commented by mr W last updated on 03/Jan/21

$$tomefactoranddivisorarethesame$$$$thing,so‘‘thefactorofthe{divisor}^{″}$$$$makesnosense.$$

Commented by PRITHWISH SEN 2 last updated on 03/Jan/21

$$\mathrm{Thank}\mathrm{you}\mathrm{sir}.$$

Commented by PRITHWISH SEN 2 last updated on 19/Jan/21

$$715\mathbf{÷}12$$$$\mathrm{factor}\mathrm{of}12=2,2,3$$$$715=357\times 2+1\left(\mathrm{first}\mathrm{dividing}\mathrm{by}2\right)$$$$357=178\times 2+1\left(\mathrm{again}\mathrm{dividing}\mathrm{by}{2}^{\mathrm{nd}}2\right)$$$$178=59\times 3+1\left(\mathrm{dividing}\mathrm{by}\mathrm{last}3\right)$$$$\therefore \mathbf{the}\mathbf{remainder}=1^{\mathbf{st}}\mathbf{remainder}\left(\mathbf{R}\right)$$$$+1^{\mathbf{st}}\mathbf{divisor}\left(\mathbf{D}\right)\times 2^{\mathbf{nd}}\mathbf{R}$$$$+1^{\mathbf{st}}\mathbf{D}\times 2^{\mathbf{nd}}\mathbf{D}\times 3^{\mathbf{rd}}\mathbf{R}$$$$=1+2\times 1+2\times 2\times 1=7$$$$$$

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