Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 12797 by tawa last updated on 01/May/17

1 + x + x^2  + ... x^(49)  = (1/2)(x^(49)  − (1/x))  Find the value of x

1+x+x2+...x49=12(x491x)Findthevalueofx

Commented by prakash jain last updated on 01/May/17

((x^(50) −1)/(x−1))=(1/2)(((x^(50) −1)/x))  x≠1,x≠0  (x^(50) −1)2x=(x−1)(x^(50) −1)  (x^(50) −1)(x+1)=0  x=−1  x^(50) =1⇒x=cos ((2kπ)/(50))+isin ((2kπ)/(50))   k=1,2,...,49  k=0⇒x=1, invalid since x≠1

x501x1=12(x501x)x1,x0(x501)2x=(x1)(x501)(x501)(x+1)=0x=1x50=1x=cos2kπ50+isin2kπ50k=1,2,...,49k=0x=1,invalidsincex1

Commented by tawa last updated on 01/May/17

God bless you sir.

Godblessyousir.

Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 01/May/17

2(x^(50) −1)=(x−1)(x^(50) −1)/x⇒  2x=x−1⇒x=−1  .■  if :x^(50) −1=0⇒ there is no solotion for x.

2(x501)=(x1)(x501)/x2x=x1x=1.if:x501=0thereisnosolotionforx.

Commented by tawa last updated on 01/May/17

God bless you sir

Godblessyousir

Terms of Service

Privacy Policy

Contact: info@tinkutara.com