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Question Number 128094 by TITA last updated on 04/Jan/21

$$\mathrm{solve}\mathrm{for}\mathrm{x}\mathrm{in}0⩽\mathrm{x}⩽2\pi$$$$\sin 2\mathrm{x}=\sec \mathrm{x}$$

Answered by MJS_new last updated on 04/Jan/21

$$\sin 2x=2\sin x\cos x$$$$\sin x=s$$$$2s\sqrt{1-s^2}=\frac{1}{\sqrt{1-s^2}}$$$$s^3-s+\frac{1}{2}=0$$$$\Rightarrow s\approx -1.19149\Rightarrow \mathrm{no}\mathrm{real}\mathrm{solution}$$

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