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Question Number 12812 by tawa last updated on 01/May/17

Answered by sandy_suhendra last updated on 02/May/17

$$1)\mathrm{V}=\pi {\mathrm{r}}^2\mathrm{t}$$$$350=3.14\times {\mathrm{r}}^2\times 8.5$$$${\mathrm{r}}^2=13.11$$$$\mathrm{r}=3.62\mathrm{cm}$$$$\mathrm{the}\mathrm{depth}\mathrm{of}\mathrm{the}\mathrm{water}=\frac{350}{8\times 7}=6.25\mathrm{cm}$$$$$$$$2)\mathrm{\Delta }\mathrm{h}=\frac{4\times 3\times 5}{3.14\times 5\times 5}=0.76\mathrm{cm}=8\mathrm{mm}$$$$$$$$3)\mathrm{r}=9\mathrm{cm}$$$$\mathrm{t}=8\mathrm{cm}$$$$\mathrm{s}=\sqrt{9^2+8^2}=12.04\mathrm{cm}$$$$\mathrm{radius}\mathrm{of}\mathrm{the}\mathrm{sector}=12.04\mathrm{cm}$$$$\alpha =\mathrm{the}\mathrm{angle}\mathrm{of}\mathrm{the}\mathrm{sector}=\frac{9}{12.04}\times 360°=269.1°$$$$$$$$4\mathrm{i})\mathrm{WY}=\sqrt{{20}^2+{14}^2}=24.4\mathrm{cm}$$$$\mathrm{the}\mathrm{length}\mathrm{of}\mathrm{the}\mathrm{slant}\mathrm{edge}=\sqrt{{10}^2+{(\frac{1}{2}\times 24.4)}^2}=15.8\mathrm{cm}$$$$\mathrm{ii}){\mathrm{h}}_1=\sqrt{15.8^2-{10}^2}=12.2\mathrm{cm}$$$${\mathrm{h}}_2=\sqrt{15.8^2-7^2}=14.2\mathrm{cm}$$$$\mathrm{the}\mathrm{surface}\mathrm{area}=20\times 14+2\times \frac{12.2\times 20}{2}+2\times \frac{14.2\times 14}{2}=723{\mathrm{cm}}^2$$$$\mathrm{iii})\mathrm{V}=\frac{1}{3}\times 20\times 14\times 10=933{\mathrm{cm}}^3$$

Commented by tawa last updated on 02/May/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{i}\mathrm{really}\mathrm{appreciate}.$$

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