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Question Number 128126 by Agnibhoo last updated on 04/Jan/21

$$\frac{4}{99}+\frac{7}{999}+\frac{11}{999999}=?$$

Answered by Geovanek last updated on 04/Jan/21

$$\frac{4}{99}+\frac{7}{99}+\frac{11}{999999}=X$$$$\mathrm{We}\mathrm{can}\mathrm{see}\mathrm{that}$$$$\frac{999999}{99}=10101\mathbf{AND}$$$$\frac{999999}{999}=1001$$$$\mathrm{So},\mathrm{we}\mathrm{have}$$$$\frac{4}{99}=\frac{4}{99}\cdot 1=\frac{4}{99}\cdot \frac{10101}{10101}=\frac{40404}{999999}\mathbf{AND}$$$$\frac{7}{999}=\frac{7}{999}\cdot 1=\frac{7}{999}\cdot \frac{1001}{1001}=\frac{7007}{999999}$$$$\mathrm{So},$$$$X=\frac{40404}{999999}+\frac{7007}{999999}+\frac{11}{999999}$$$$X=\frac{40404+7007+11}{999999}$$$$X=\frac{47422}{999999}$$$$\mathrm{You}\mathrm{can}\mathrm{to}\mathrm{use}\mathrm{a}\mathrm{calculator}\mathrm{for}\mathrm{this}\mathrm{division}.$$

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