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Question Number 128146 by sahnaz last updated on 04/Jan/21

$$4<\mathrm{x}<5\mathrm{a}=\sqrt{\mathrm{x}-3+2\sqrt{\mathrm{x}-4}}\mathrm{b}=\sqrt{\mathrm{x}-4}-1\mathrm{x}-\mathrm{a}\times \mathrm{b}=?$$

Answered by Fikret last updated on 04/Jan/21

$$a=\sqrt{x-4}+1$$ $$b=\sqrt{x-4}-1$$ $$a.b=x-5$$ $$x-x+5=5$$

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