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Question Number 128276 by john_santu last updated on 06/Jan/21
∫e2∞dxx3lnx?
Answered by liberty last updated on 06/Jan/21
ϝ=limY→+∞∫e2Ydxx3.lnx=limY→+∞(−12ln2x)e2Yϝ=limY→+∞(18−12ln2Y)=18
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