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Question Number 128333 by liberty last updated on 06/Jan/21

$$\mathrm{Prove}\mathrm{that}\tan 30°{30}^{\prime }=\sqrt{6}+\sqrt{2}-\sqrt{3}-2$$

Commented by MJS_new last updated on 06/Jan/21

$$\mathrm{not}\mathrm{true}?!$$$$\tan (7.5°+180°\times n)=-2+\sqrt{2}-\sqrt{3}+\sqrt{6}$$

Commented by liberty last updated on 07/Jan/21

$$\mathrm{yes}.\mathrm{i}\mathrm{think}\mathrm{it}\mathrm{true}\mathrm{for}\tan 7°{30}^{\prime }$$

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