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Question Number 128341 by liberty last updated on 06/Jan/21

$$\mathrm{Which}\mathrm{is}\mathrm{larger}\mathrm{Z}=\frac{1}{2+\frac{3}{6-\frac{4}{11}}}\mathrm{or}\mathrm{S}=\frac{1}{2+\frac{3}{6-\frac{5}{11}}}?$$

Commented by mr W last updated on 06/Jan/21

$$withoutcalculation:$$$$Z:larger\nearrow smaller\nearrow larger$$$$\Rightarrow ZislargerthanS.$$

Commented by MJS_new last updated on 06/Jan/21

$${\mathrm{I}}^{\prime }\mathrm{m}\mathrm{afraid}{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{the}\mathrm{other}\mathrm{way}\mathrm{round}...$$

Commented by mr W last updated on 06/Jan/21

$$yessir,imisread.$$

Commented by MJS_new last updated on 06/Jan/21

$$\mathrm{I}\mathrm{thought}\mathrm{so}$$

Commented by liberty last updated on 07/Jan/21

$$\mathrm{hahahaha}===$$

Answered by bramlexs22 last updated on 07/Jan/21

$$\mathrm{Z}=\frac{1}{2+\frac{3}{\frac{62}{11}}}=\frac{1}{2+\frac{33}{62}}=\frac{62}{157}\approx 0.3949$$$$\mathrm{S}=\frac{1}{2+\frac{3}{\frac{61}{11}}}=\frac{1}{2+\frac{33}{61}}=\frac{61}{155}\approx 0.3935$$$$\mathrm{then}\mathrm{Z}>\mathrm{S}$$$$$$

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