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Question Number 128371 by aliibrahim1 last updated on 06/Jan/21

Commented by MJS_new last updated on 06/Jan/21

$$A_n=\frac{752\underset{k=1}{\sum ^n}\frac{1}{2k-1}-752\underset{k=1}{\sum ^n}\frac{1}{2k}}{2\underset{k=1}{\sum ^n}\frac{1}{n+k}}$$$$A_n=376$$$$(\mathrm{just}\mathrm{try}\mathrm{the}\mathrm{first}\mathrm{few}n=1,2,3,...\mathrm{to}\mathrm{see})$$

Answered by MJS_new last updated on 06/Jan/21

$$376$$

Commented by aliibrahim1 last updated on 06/Jan/21

$$canutellmehow$$

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