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Question Number 128373 by BHOOPENDRA last updated on 06/Jan/21
∫01x32(1−x)12dx
Answered by Dwaipayan Shikari last updated on 06/Jan/21
∫01x32(1−x)12dx=β(52,32)=Γ(52)Γ(32)Γ(4)=38.6Γ2(12)=π.π16=π16
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