Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 128511 by benjo_mathlover last updated on 08/Jan/21

$$\mathcal{H}=\int \frac{{2017\mathrm{x}}^{2016}+{2018\mathrm{x}}^{2017}}{1+{\mathrm{x}}^{4034}+{2\mathrm{x}}^{4035}+{\mathrm{x}}^{4036}}\mathrm{dx}$$

Answered by liberty last updated on 08/Jan/21

$$\mathcal{H}=\int \frac{{2017\mathrm{x}}^{2016}+{2018\mathrm{x}}^{2017}}{1+{({\mathrm{x}}^{2017}+{\mathrm{x}}^{2018})}^2}\mathrm{dx}$$$$\mathcal{H}=\int \frac{\mathrm{d}\ell }{1+{\ell }^2};\mathrm{where}\ell ={\mathrm{x}}^{2017}+{\mathrm{x}}^{2018}$$$$\mathcal{H}=\arctan ({\mathrm{x}}^{2017}+{\mathrm{x}}^{2018})+\mathrm{C}$$

Commented by bramlexs22 last updated on 08/Jan/21

$$\mathrm{waw}....$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com