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Question Number 128589 by mnjuly1970 last updated on 08/Jan/21

...nice calculus... a∈R^+ & }⇒ (√(a−(√a) )) =? a^2 −17a=16(√a)

...nicecalculus... a∈R+ &}⇒a−a=? a2−17a=16a

Answered by snipers237 last updated on 08/Jan/21

(a−(√a))(a+(√a))=16(a+(√a))⇒(√(a−(√a))) ∈{0,4}

(a−a)(a+a)=16(a+a)⇒a−a∈{0,4}

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