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Question Number 128745 by shaker last updated on 10/Jan/21

Answered by liberty last updated on 10/Jan/21

$$\underset{x\to 0}{\lim }\frac{(1+\mathrm{mnx}+\frac{\mathrm{n}(\mathrm{n}-1)}{2}{\mathrm{m}}^2{\mathrm{x}}^2)-(1+\mathrm{mnx}+\frac{\mathrm{m}(\mathrm{m}-1)}{2}{\mathrm{n}}^2{\mathrm{x}}^2)}{{\mathrm{x}}^2}=$$$$\frac{{\mathrm{m}}^2({\mathrm{n}}^2-1)-{\mathrm{n}}^2({\mathrm{m}}^2-1)}{2}=\frac{{\mathrm{n}}^2-{\mathrm{m}}^2}{2}$$

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