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Question Number 12881 by kunalshukla95040 last updated on 05/May/17
limx→01−cosxxisequalsto.
Answered by nume1114 last updated on 05/May/17
limx→01−cosxx=limx→01−(1−2sin2(x2))x=limx→02sin(x2)2⋅x2=22limx→0sin(x2)x2=22(or12)
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