Question Number 12895 by tawa last updated on 06/May/17
Commented by tawa last updated on 06/May/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$
Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 07/May/17
$${S}=\left(\mathrm{4}+\frac{\mathrm{12}}{\mathrm{2}}−\mathrm{1}\right)×\mathrm{4}=\mathrm{36} \\ $$
Answered by ajfour last updated on 06/May/17
![[(π/4)(12)^2 −(1/2)(12)(12)]−[(π/4)(4)^2 −(1/2)(4)(4)] =(36π−72)−(4π−8) =32π−64 .](Q12904.png)
$$\left[\frac{\pi}{\mathrm{4}}\left(\mathrm{12}\right)^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{12}\right)\left(\mathrm{12}\right)\right]−\left[\frac{\pi}{\mathrm{4}}\left(\mathrm{4}\right)^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{4}\right)\left(\mathrm{4}\right)\right] \\ $$$$=\left(\mathrm{36}\pi−\mathrm{72}\right)−\left(\mathrm{4}\pi−\mathrm{8}\right) \\ $$$$=\mathrm{32}\pi−\mathrm{64}\:. \\ $$
Commented by tawa last updated on 06/May/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$
Commented by chux last updated on 07/May/17
$$\mathrm{please}\:\mathrm{explain}\:\mathrm{further} \\ $$
Commented by ajfour last updated on 07/May/17
