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Question Number 12903 by tawa last updated on 06/May/17

Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 06/May/17

$${\mathit{y}}^{{}^{\prime }}=6\mathit{x}-1\Rightarrow {\mathit{m}}_{\mathit{t}}=6\times 1-1=5$$$$\mathit{y}-{\mathit{y}}_{\mathit{t}}={\mathit{m}}_{\mathit{t}}(\mathit{x}-{\mathit{x}}_{\mathit{t}})\Rightarrow \mathit{y}-2=5(\mathit{x}-1)$$$$\mathit{y}=0\Rightarrow \mathit{x}-1=\frac{-2}{5}\Rightarrow \mathit{x}=\frac{3}{5}\Rightarrow \mathit{P}(\frac{3}{5},0).◼$$

Commented by tawa last updated on 06/May/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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