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Question Number 129034 by oustmuchiya@gmail.com last updated on 12/Jan/21
Differentiatesiny−x2y3−cosx=3y
Answered by MJS_new last updated on 12/Jan/21
(cosy−3x2y2)dy+(−2xy3+sinx)dx=3dy⇒dydx=sinx−2xy33x2y2+3−cosy
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