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Question Number 129039 by oustmuchiya@gmail.com last updated on 12/Jan/21

$$partiallyDifferentiatefunction$$$$\mathit{f}(\mathit{x},\mathit{y})=2{\mathit{x}}^{-2}\mathit{y}+{\mathit{x}\mathit{y}}^3+\frac{2}{{\mathit{x}}^2\mathit{y}}$$

Answered by liberty last updated on 12/Jan/21

$$\mathrm{f}(\mathrm{x},\mathrm{y})={2\mathrm{x}}^{-2}\mathrm{y}+{\mathrm{xy}}^3+{2\mathrm{x}}^{-2}{\mathrm{y}}^{-1}$$$$\{\begin{array}{l}\frac{\partial \mathrm{f}}{\partial \mathrm{x}}=-{4\mathrm{x}}^{-3}\mathrm{y}+{\mathrm{y}}^3-{4\mathrm{x}}^{-3}{\mathrm{y}}^{-1}\\ \frac{\partial \mathrm{f}}{\partial \mathrm{y}}={2\mathrm{x}}^{-2}+{3\mathrm{xy}}^2-{2\mathrm{x}}^{-2}{\mathrm{y}}^{-2}\end{array}$$

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