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Question Number 129041 by oustmuchiya@gmail.com last updated on 12/Jan/21

$$Differentiate\mathit{f}\left(\mathit{x}\right)={({\mathit{x}}^2+4)}^3\left(6{\mathit{x}}^2\right)$$

Answered by bramlexs22 last updated on 12/Jan/21

$$\mathrm{f}{}^{\prime }\left(\mathrm{x}\right)=12\mathrm{x}{({\mathrm{x}}^2+4)}^3+6\mathrm{x}{({\mathrm{x}}^2+4)}^2\left({6\mathrm{x}}^2\right)$$

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