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Question Number 129087 by Adel last updated on 12/Jan/21

Answered by MJS_new last updated on 12/Jan/21

$$2^{10}10!\left(1\times 3\times 5\times 7\times 9\times 11\times 13\times 15\times 17\times 19\right)=$$$$=10!\times 11\times \left(3\times 2^2\right)\times 13\times \left(7\times 2\right)\times 15\times \left(2^4\right)\times 17\times \left(9\times 2\right)\times 19\times \left(5\times 2^2\right)=$$$$=20!$$

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