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Question Number 129212 by bramlexs22 last updated on 13/Jan/21
M=∫x+x2+5dx?
Answered by TheSupreme last updated on 13/Jan/21
x+x2+5=t
Answered by MJS_new last updated on 13/Jan/21
∫x+x2+5dx=[t=x+x2+5→dx=t4+5t3dt]=∫t4+5t2dt=t4−153t==2(2x−x2+5)x+x2+53+C
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