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Question Number 129234 by bemath last updated on 14/Jan/21
cos247°+cos273°+cos47°cos73°+12=?
Answered by liberty last updated on 14/Jan/21
(cos73°+cos47°)2−cos73°cos47°+12=(2cos60°cos13°)2−12(cos120°+cos26°)+12=cos213°−12(−12+2cos213°−1)+12=cos213°+34−cos213°+12=54
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