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Question Number 129275 by abdurehime last updated on 14/Jan/21
∫exxdx??????
Commented by abdurehime last updated on 14/Jan/21
noone????
Commented by Dwaipayan Shikari last updated on 14/Jan/21
∑∞n=11n!∫(xx)ndx=∑∞n=11n!∫(xx)n=∑∞n=11n!∫enxlogxdx=∑∞n=1∑∞k=11n!.nkk!∫(xlogx)kdx=∑n⩾1∑k⩾1nkn!k!∫tke(k+1)tdtlogx=t=∑n⩾1∑k⩾1nkn!k!∑m⩾1∫tk(k+1)mtmm!dt=∑n⩾1∑k⩾1∑m⩾1nk(k+1)m(logx)k+m+1n!k!m!(k+m+1)+C
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