Question and Answers Forum

All Questions      Topic List

Trigonometry Questions

Previous in All Question      Next in All Question      

Previous in Trigonometry      Next in Trigonometry      

Question Number 12930 by tawa last updated on 07/May/17

Answered by ajfour last updated on 07/May/17

Commented by ajfour last updated on 07/May/17

$$byparallelaxestheorem:$$$$\frac{DF}{a+c}=\frac{b}{a+b+c}.....\left(i\right)$$$$\frac{EG}{a+b}=\frac{c}{a+b+c}.......\left(ii\right)$$$$herewealsohave$$$${(a+b)}^2+{(a+c)}^2={(a+b+c)}^2$$$${(a+b)}^2+a^2+2ac+c^2=$$$${(a+b)}^2+c^2+2(a+b)c$$$$\Rightarrow a^2=2bc....\left(iii\right)$$$$from\left(i\right)\mathrm{\&}\left(ii\right):$$$$DF+EG=\frac{ab+bc}{a+b+c}+\frac{ac+bc}{a+b+c}$$$$=\frac{ab+2bc+ac}{a+b+c}$$$$=\frac{ab+a^2+ac}{a+b+c}$$$$=\frac{a(a+b+c)}{a+b+c}=a=DE$$$$=2017.$$$$$$$$$$

Commented by tawa last updated on 07/May/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Commented by tawa last updated on 07/May/17

$$\mathrm{Please}\mathrm{sir}\mathrm{what}\mathrm{is}\mathrm{the}\mathrm{name}\mathrm{of}\mathrm{the}\mathrm{application}\mathrm{you}\mathrm{used}\mathrm{to}\mathrm{draw}\mathrm{the}\mathrm{diagram}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com