Question Number 129323 by harckinwunmy last updated on 14/Jan/21
$${In}\:{a}\:{competition}\:{there}\:{are}\:\mathrm{200}\:{children},\:\mathrm{50}\:{are}\:{men} \\ $$$${the}\:{rest}\:{are}\:{women}.\:{If}\:{the}\:{probability}\:{of}\:{selecting}\:{a}\: \\ $$$${child}\:{is}\:\mathrm{0}.\mathrm{05},\:{how}\:{many}\:{are}\:{the}\:{competitor}? \\ $$
Answered by Ar Brandon last updated on 15/Jan/21
$$\frac{\mathrm{200}}{\mathrm{200}+\mathrm{50}+\mathrm{x}}=\mathrm{0}.\mathrm{05}=\frac{\mathrm{1}}{\mathrm{20}} \\ $$$$\Rightarrow\mathrm{4000}=\mathrm{200}+\mathrm{50}+\mathrm{x}\:\Rightarrow\mathrm{x}=\mathrm{3750}\:\mathrm{women} \\ $$$$\mathrm{Total}=\mathrm{200}+\mathrm{50}+\mathrm{3750}=\mathrm{4000}\:\mathrm{competitors} \\ $$