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Question Number 129378 by BHOOPENDRA last updated on 15/Jan/21

Answered by Dwaipayan Shikari last updated on 15/Jan/21

$$\mathcal{L}({ut}^2{e}^{-2t}-{ute}^{-2t})=u{\int }_0^{\mathrm{\infty }}{t}^2{e}^{-(s+2)t}-u{\int }_0^{\mathrm{\infty }}{te}^{-(s+2)t}dt$$$$=\frac{2u}{{(s+2)}^3}-\frac{u}{{(s+2)}^2}$$

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