Question Number 129527 by MathSh last updated on 16/Jan/21 | ||
$${f}\left({x}\right)=\begin{cases}{\mathrm{5}−{x}\:;\:{x}\geqslant\mathrm{2}}\\{{x}^{\mathrm{2}} +\mathrm{3}\:;\:{x}<\mathrm{2}}\end{cases}\:\:\:{if}, \\ $$ $${find}:\:{f}\left(\mathrm{2}\right)+{f}\left(\mathrm{0}\right)=? \\ $$ | ||
Commented bybramlexs22 last updated on 16/Jan/21 | ||
$$=\:\mathrm{3}\:+\:\mathrm{3}\:=\:\mathrm{6} \\ $$ | ||