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Question Number 129727 by abdurehime last updated on 18/Jan/21
finddydxifx2+y2=4
Answered by Ar Brandon last updated on 18/Jan/21
y=±4−x22x+2ydydx=0⇒dydx=−xydydx=∓x4−x2
Answered by Adel last updated on 18/Jan/21
2x+2ydydx=0⇒dydx=−xydanish
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