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Question Number 129758 by I want to learn more last updated on 18/Jan/21

$$\mathrm{Find}\mathrm{the}\mathrm{nth}\mathrm{derivatives}\mathrm{of}{\log }_{\mathrm{e}}{(6\mathrm{x}+8)}^5$$

Commented by Dwaipayan Shikari last updated on 18/Jan/21

$$f\left(x\right)=5log(6x+8)$$$$f^{\prime }\left(x\right)=\frac{30}{6x+8}$$$$f^{″}\left(x\right)=-\frac{180}{{(6x+8)}^2}$$$$f^n\left(x\right)={(-1)}^{n+1}\frac{5.6^n}{{(6x+8)}^n}={(-1)}^{n+1}\frac{5.3^n}{{(3x+4)}^n}$$

Commented by I want to learn more last updated on 18/Jan/21

$$\mathrm{I}\mathrm{appreciate}\mathrm{sir}.\mathrm{Thanks}.$$

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