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Question Number 129788 by bramlexs22 last updated on 19/Jan/21
∫(1+3x3)ex3dx
Answered by EDWIN88 last updated on 19/Jan/21
letz=xex3⇒dz=(ex3+x.(3x2ex3))dxdz=(1+3x3)ex3dxI=∫dz=z+c=xex3+C
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