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Question Number 129985 by Dwaipayan Shikari last updated on 21/Jan/21

θ^(••) (t)−(γ/(ml))θ^• (t)+(g/l)sinθ(t)=0

θ(t)γmlθ(t)+glsinθ(t)=0

Answered by Olaf last updated on 21/Jan/21

θ^(••) −(γ/(ml))θ^• +(g/l)sinθ = 0 (1)  1st case : θ ≈ 0 (θ_(0 ) ≤ 10°)  (1) : θ^(••) −(γ/(ml))θ^• +(g/l)θ = 0  r^2 −(γ/(ml))r+(g/l) = 0  ...    2nd case : γ ≪ ml ((γ/(ml)) ≈ 0)  (1) : θ^(••) +(g/l)sinθ = 0  θ^(••) θ^• +(g/l)θ^• sinθ = 0  (1/2)θ^2 ^(•) −(g/l)cosθ = C_1   (θ^• /( (√(C_2 −((2g)/l)cosθ)))) = ±1  ...  (Elliptic functions, Jacobi)

θγmlθ+glsinθ=0(1)1stcase:θ0(θ010°)(1):θγmlθ+glθ=0r2γmlr+gl=0...2ndcase:γml(γml0)(1):θ+glsinθ=0θθ+glθsinθ=012θ2glcosθ=C1θC22glcosθ=±1...(Ellipticfunctions,Jacobi)

Commented by Dwaipayan Shikari last updated on 21/Jan/21

Is it possible to solve it simaltaneously?  Including  (γ/(ml))θ^•  and (g/l)sinθ   ?

Isitpossibletosolveitsimaltaneously?Includingγmlθandglsinθ?

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