using De Moivre theorem solve the equation (x+1)^5 +(x−1)^5 =0


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Question Number 13005 by 1630321995 last updated on 10/May/17

$u s i n g D e M o i v r e t h e o r e m s o l v e t h e e q u a t i o n {(x + 1)}^{5} + {(x - 1)}^{5} = 0$
	Answered by mrW1 last updated on 10/May/17

	${(x + 1)}^{5} - {(1 - x)}^{5} = 0$ ${(x + 1)}^{5} = {(1 - x)}^{5}$ $x + 1 = 1 - x$ $2 x = 0$ $\Rightarrow x = 0$
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